63x^2-3x-30=0

Solution for 63x^2-3x-30=0 equation:

63x^2-3x-30=0

a = 63; b = -3; c = -30;
Δ = b2-4ac
Δ = -32-4·63·(-30)
Δ = 7569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7569}=87$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-87}{2*63}=\frac{-84}{126}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+87}{2*63}=\frac{90}{126}
=5/7
$